Bill and Eugene left the airport at the same time. They traveled in opposite directions. Eugene traveled 21.1 km/h faster than Bill. After one hour they were 133.7 km apart. Find Bill's speed and show work.

Answer:56.3 kilometers per hourStep-by-step explanation:We know D = RTwhereD is distanceR is rate (speed)T is timeLet's Bill's rate be "x". Thus using equation we can write:D = xtWe know Eugene travelled 21.1 faster than Bill, so Eugene's rate is 21.1 + x. So we can write:D = (21.1 + x)tD = 21.1t + xtNow, putting t = 1 in both since after 1 hour given, we have:D = x(1)D = xandD = 21.1(1) + x(1)D = 21.1 + xWe know the sum of both the distance is 133.7, so we can write:x + 21.1 + x = 133.7Solving for x:2x = 133.7 - 21.1 2x = 112.6x = 112.6 / 2x = 56.3 km/hrThis is Bill's rate: 56.3 kilometers per hour